2[d-(2d+10)+5]=2(d+5)

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Solution for 2[d-(2d+10)+5]=2(d+5) equation:


Simplifying
2[d + -1(2d + 10) + 5] = 2(d + 5)

Reorder the terms:
2[d + -1(10 + 2d) + 5] = 2(d + 5)
2[d + (10 * -1 + 2d * -1) + 5] = 2(d + 5)
2[d + (-10 + -2d) + 5] = 2(d + 5)

Reorder the terms:
2[-10 + 5 + d + -2d] = 2(d + 5)

Combine like terms: -10 + 5 = -5
2[-5 + d + -2d] = 2(d + 5)

Combine like terms: d + -2d = -1d
2[-5 + -1d] = 2(d + 5)
[-5 * 2 + -1d * 2] = 2(d + 5)
[-10 + -2d] = 2(d + 5)

Reorder the terms:
-10 + -2d = 2(5 + d)
-10 + -2d = (5 * 2 + d * 2)
-10 + -2d = (10 + 2d)

Solving
-10 + -2d = 10 + 2d

Solving for variable 'd'.

Move all terms containing d to the left, all other terms to the right.

Add '-2d' to each side of the equation.
-10 + -2d + -2d = 10 + 2d + -2d

Combine like terms: -2d + -2d = -4d
-10 + -4d = 10 + 2d + -2d

Combine like terms: 2d + -2d = 0
-10 + -4d = 10 + 0
-10 + -4d = 10

Add '10' to each side of the equation.
-10 + 10 + -4d = 10 + 10

Combine like terms: -10 + 10 = 0
0 + -4d = 10 + 10
-4d = 10 + 10

Combine like terms: 10 + 10 = 20
-4d = 20

Divide each side by '-4'.
d = -5

Simplifying
d = -5

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